Baking Soda Lab!!!

Baking Soda Lab

Purpose: To find the experimental mole ratio of the reaction of baking soda with vinegar

Background: Baking soda is pure sodium hydrogen carbonate (NaHCO₃) Vinegar is an aqueous solution of acetic acid (HC₂H₃O₂)

Balanced Equation: NaC₂H₃O₂ + HC₂H₃O₂ à CO₂ + H₂O + NaC₂H₃O₂

Mole Ratio of Balanced Equation: 1 to 1

Materials: 20ml vinegar in a large pipette

                  Balance

                  100ml beaker

                  1 Gram Baking Soda

Procedure:

1. Get a large plastic pipette filled with vinegar. Measure the mass of the pipette and record the mass

2. Measure the mass of an empty, clean 00 ml beaker

3. Transfer about 1 gram of baking soda to the beaker. Record the exact mass of the beaker with the powder

4. Add vinegar, from the pipette, to the beaker. Swirl the contents and observe the reaction. Continue to add vinegar until no more bubbles are produced. This will take a while so be patient and pay close attention to the reaction

5. Find the mass of the left-over vinegar in the pipette and record. Subtract the original mass of this pipette to find the mass of the vinegar used in the reaction

Initial Mass of Pipette in Grams	1.36 Grams
Final Mass of Pipette at End of Reaction	2.52 Grams
Net Mass of Vinegar Used in Reaction	9.81 Grams
Mass of Empty Beaker	113.73 Grams
Mass of Beaker and Baking Soda	114.73 Grams
Net Mass of Baking Soda	1 Gram

Conclusion Questions:

1.     Calculate the moles of sodium hydrogen carbonate used from the net mass of the baking soda.

1gNaHCO₃ × 1 mole / 81g NaHCO₃ = .0123 moles

2.     There are 5 grams of acetic acid per 100 grams of vinegar. Calculate the grams of acetic acid added to the beaker for the reaction.

5% of 9.81 = .49 grams of acetic acid

3.     Calculate the moles of acetic acid used in the reaction.

.49gHC₂H₃O₂ × 1 mole / 60g HC₂H₃O₂ = .0081 moles

4.     Compare the moles of sodium hydrogen carbonate with the moles of acetic acid used in this experiment. Find the nearest whole number ration between the two values.

Experimental Ratio: 2 to 3

5.     The ratio calculated above is your experiment mole ratio. Is this mole ration the same as the mole ratio in the balance equation?

No, due to rounding errors along with weighing errors resulted in the chance in the results.